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Two resistors R(1) = 400 Omega and R(2)...

Two resistors `R_(1) = 400 Omega and R_(2) = 20 Omega` are connected in parallel to a battery. If heating power developed in `R_(1)` is 25. W. find the heating power developed in `R_(2)`.

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To solve the problem step by step, we will use the relationship between power, resistance, and voltage in a parallel circuit. ### Step 1: Understand the given values We have two resistors: - \( R_1 = 400 \, \Omega \) - \( R_2 = 20 \, \Omega \) The power developed in resistor \( R_1 \) is given as: ...
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