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A coil of self inductance 2.5 H and resi...

A coil of self inductance 2.5 H and resistance `20 Omega` is connected to a battery of emf 120 V having internal resistance of `5 Omega`. Find :
The current in the circuit in steady state.

Text Solution

Verified by Experts

`i_(0)=(E)/(R+r)=(120)/(20+5)`
`=4*8A`
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