Calculate magnetic flux density of the magnetic field at the centre of a circular coil of 50 turns, having radius of 0.5 m and carrying a current of 5A.

Explanation

To calculate the magnetic flux density (B) at the center of a circular coil, we can use the formula derived from the Biot-Savart law:

\[ B = \frac{\mu_0 n I}{2R} \]

where:
- \( \mu_0 \) is the permeability of free space, approximately \( 4\pi \times 10^{-7} \, \text{T m/A} \)
- \( n \) is the number of turns in the coil
- \( I \) is the current flowing through the coil
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