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The horizontal component of earth.s magn...

The horizontal component of earth.s magnetic field On at a place is `1/sqrt3` times the vertical component. Determine the angle of dip at that place.

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To solve the problem, we need to determine the angle of dip (δ) at a place where the horizontal component of the Earth's magnetic field (H) is \( \frac{1}{\sqrt{3}} \) times the vertical component (V). ### Step-by-Step Solution: 1. **Define the Components**: - Let the vertical component of the magnetic field be \( V = V_b \). - The horizontal component of the magnetic field is given as \( H = \frac{1}{\sqrt{3}} V_b \). ...
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