In Young.s double slit experiment using monochromatic light of wavelength 600 nm, 5th bright fringe is at a distance of 0.48 mm from the centre of the pattern. If the screen is at a distance of 80 cm from the plane of the two slits, calculate :
Distance between the two slits.

Explanation

To solve the problem, we will use the formula for the position of the bright fringes in Young's double slit experiment:

\[ Y_n = \frac{n \lambda D}{d} \]

Where:
- \( Y_n \) is the position of the nth bright fringe from the center of the pattern.
- \( n \) is the order of the bright fringe (in this case, \( n = 5 \)).
- \( \lambda \) is the wavelength of the light used (in meters).
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