In Young.s double slit experiment using monochromatic light of wavelength 600 nm, 5th bright fringe is at a distance of 0.48 mm from the centre of the pattern. If the screen is at a distance of 80 cm from the plane of the two slits, calculate :
Fringe width, i.e., fringe separation.

Explanation

To solve the problem of calculating the fringe width in Young's double slit experiment, we will follow these steps:

### Given Data:
- Wavelength (λ) = 600 nm = \(600 \times 10^{-9}\) m
- Distance of the 5th bright fringe from the center (y₅) = 0.48 mm = \(0.48 \times 10^{-3}\) m
- Distance from the slits to the screen (D) = 80 cm = \(0.80\) m

### Step 1: Understand the relationship between fringe width and the given parameters
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