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A beam of light is incident at the polar...

A beam of light is incident at the polarizing angle of `35^(@)` on a certain glass plate. The refractive index of the glass plate is:

A

`sin 35^(@)`

B

`tan 35^(@)`

C

`tan 55^(@)`

D

`sin 55^(@)`

Text Solution

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The correct Answer is:
To find the refractive index of the glass plate using the given polarizing angle, we can follow these steps: ### Step 1: Understand the relationship between the refractive index and the polarizing angle. The refractive index (μ) of a medium can be calculated using the formula: \[ \mu = \tan(I_p) \] where \(I_p\) is the polarizing angle. ### Step 2: Identify the given polarizing angle. From the question, we know that the polarizing angle \(I_p\) is given as \(35^\circ\). ### Step 3: Substitute the polarizing angle into the formula. Now, we substitute \(I_p\) into the formula: \[ \mu = \tan(35^\circ) \] ### Step 4: Calculate the value of \(\tan(35^\circ)\). Using a scientific calculator or trigonometric tables, we find: \[ \tan(35^\circ) \approx 0.7002 \] ### Step 5: State the refractive index. Thus, the refractive index of the glass plate is: \[ \mu \approx 0.7002 \] ### Final Answer: The refractive index of the glass plate is approximately \(0.7002\). ---

To find the refractive index of the glass plate using the given polarizing angle, we can follow these steps: ### Step 1: Understand the relationship between the refractive index and the polarizing angle. The refractive index (μ) of a medium can be calculated using the formula: \[ \mu = \tan(I_p) \] where \(I_p\) is the polarizing angle. ...
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