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Copy and complete the following table fo...

Copy and complete the following table for a radioactive element whose half-life is 10 minutes. Assume that you have 30g of this element at t= 0.

Text Solution

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`because N = (N_(0))/(2^(n))`, n being no. of half-life spent
t=20 min means 2 half-life and t= 30 min means 3 half-life.
`therefore N_(20 "min")= (N_(0))/(2^(2))= (N_(0))/(4) and N_("30 min")= (N_(0))/(2^(3)) = (N_(0))/(8)`
`therefore m_(20"min")= (m_(0))/(4)= (30gm)/(4)= 7.5gm`
and `m_(30"min")= (m_(0))/(8) = (30gm)/(8)= 3.75gm`
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