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Obtain the balancing condition for the W...

Obtain the balancing condition for the Wheatstone bridge arrangement as shown in Figure 4 below:

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In wheatstone.s bridge, four resistances are joined to form a parallelogram. In one diagonal of this parallelogram a galvanometer is attached, and in other diagonal, a cell. The values of resistances are so adjusted that no current flows through the galvanometer. This condition of bridge is called balanced wheatstone.s bridge condition. Let P, Q, R and S resistances forms a bridge. Let a current, I flow through the circuit.

Applying Kirchhoff.s second law to closed loop ABDA, `I_(1)P- I_(2)R= 0 or I_(1)P= I_(2)R`
Applying Kirchhoff.s second law to closed loop BCDB, `I_(1)Q- I_(2)S= 0 or I_(1)Q= I_(2)S` ....(ii)
Dividing equation (i) by equation (ii), `(I_(1)P)/(I_(1)Q) = (I_(2)R)/(I_(2)S) rArr (P)/(Q) = (R )/(S)`
This is the balanced wheatstone bridge condition.
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