Home
Class 12
PHYSICS
An a.c., source of emf epsi= 200 sin ome...

An a.c., source of emf `epsi= 200 sin omega t` is connected to a resistor of `50Omega`. Calculate:
Average current `(I_(avg))`

Text Solution

AI Generated Solution

To find the average current \( I_{\text{avg}} \) through a resistor when connected to an alternating current (AC) source, we can follow these steps: ### Step 1: Identify the given values The given EMF of the AC source is: \[ \epsilon(t) = 200 \sin(\omega t) \] The resistance \( R \) is: ...
Promotional Banner

Similar Questions

Explore conceptually related problems

An a.c., source of emf epsi= 200 sin omega t is connected to a resistor of 50Omega . Calculate: Root mean square (rms) value of emf

An Ac source of volatage V=100 sin 100pit is connected to a resistor of resistance 20 Omega .The rms value of current through resistor is ,

When an a.c source is connected across a resistor

A cell of e.m.f. ε and internal resistance r sends a current of 1.0 A when it is connected to an external resistance of 1.9 Omega . But it sends a current of 0.5 A when it is connected to an resistance of 3.9 Omega calculate the values of epsi and r .

An AC source producing emf V=V_(0) [sin omega t+sin 2 omega t] is connected in series with a capacitor and a resistor. The current found in the circuit is i=i1sin 'omega' t +fi 1

A 20 mu F capacitor, 0.2 H inductor and a 50 Omega resistor are connected in series to an a.c. Source whose emf is given by E = 310 sin (314 t) where E is in volt and t is in second. Calculate : peak value of current in the circuit.

An a.c. voltage of (V = 100 sin omega t) volt is connected across the parallel combination of inductor and capacitor having ( X_L = 5 Omega) and (X_C = 10 Omega) then current supplied by source is (in ampere)

An a.c. source of angular frequency omega is fed across a resistor R and a capacitor C in series. The current registered is I. If now the frequency of the source is changed to omega//3 (but maintaining the same voltage), the current in the circuit is found to be halved. calculate the ratio of reactance to resistance at the original frequency omega .

An A.C. generator generating an emf E given by E = 311 sin(10t) is connected to a 44 Omega resistor. Calculate : (i) rms value of A.C. flowing through the resistor. (ii) frequency of the current (iii)mean value of emf generated by the generator in time interval 0.06 to 0.08s.

An inductor (L = 200 mH) is connected to an AC source of peak emf 210 V and frequency 50 Hz . Calculate the peak current. What is the instantaneous voltage of the source when the current is at its peak value?