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Two particles of mass m and 2m with char...

Two particles of mass `m` and `2m` with charges 2q and q are placed in a uniform electric field E and allowed to move for same time. Find the ratio of their kinetic energie

A

`2:1`

B

`8:1`

C

`4:1`

D

`1:4`

Text Solution

Verified by Experts

The correct Answer is:
A

`(KE_(A))/(KE_(B)) =(1//2 m_(A) v_(A)^(2))/(1//2m_(B)v_(B)^(2))`
`v_(A) =u_(A) +a_(A)t`
`v_(A) =(2qE)/(m) t`
`v_(B)=(2qE)/(2m)t`
`:. (KE_(A))/(KE_(B))=(1//2m(2qEt//m)^(2))/(1//2" "2m(2qEt//2m)^(2))`
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