7.A particle A of mass 10/7kg is moving in the positive direction of x .Its initial position is x=0 & initial velocity is 1m/s .The velocity at x=10 is: (use the graph given)

A particle A of mass 10//7kg is moving in the positive direction of x-axis . At initial position x=0 , its velocity is 1ms^-1 , then its velocity at x=10m is (use the graph given)

A particle is moving on a straight line with constant retardation of 1 m//s^(2) . Its initial velocity is 10 m//s .

A particle moving in the positive x-direction has initial velocity v_(0) . The particle undergoes retardation kv^(2) , where vis its instantaneous velocity. The velocity of the particle as a function of time is given by:

The x-t curve shown in the figure provides following position x_(0) = Initial position v_(0) = initial velocity , a = acceleration

A particle starts from rest at the origin and moves along the positive x direction. Its acceleration a versus position x graph is shown in the figure. The velocity of the particle at x = 6 m is?

The velocity of a particle moving in the positive direction of x-axis veries as v=10sqrtx . Assuming that at t=0 , particle was at x=0

A particle of mass 0.01 kg having position vector vecr = ( 10 hati + 6 hatj) meters is moving with a velocity 5 hati m/s . Calculate its angular momentum about the origin.

A particle is moving along x-direction with a constant acceleration a. The particle starts from x=x_0 position with initial velocity u. We can define the position of the particle with time by the relation x=x_0+ut+(1)/(2)at^2 plot the position of the particle in relation with time is following situations (i) If initial position of the particle is on negativ x-axis, initial velocity is positive and acceleration is negative. (ii) If initial position is positive, initial velocity is negative and acceleration is positive.

A uniform cube of mass m and edge a moves on a horizontal surface along the positive x-axis, with initial velocity v_(0) . Then