`P_(A)and P_(B)` are the vapour pressure of pure liquid components ,Aand B respectively of an ideal binary solution,If `x_(A)` represents the mole fraction of component A, the total pressure of the solution will be

If P^(@) and P_(5) are the vapour pressure of the solvent and its solution respectively and x_(1) and x_(2) are the mole fraction of the solvent and solute respectively, then

The vapour pressures of pure liquids A and B are 0.600 bar and 0.933 bar respectively, at a certain temperature. What is the mole fraction of solute when the total vapour pressure of their mixture is 0.8 bar?

If p^(@) and p_(a) are the vapour pressures of the solvent and solution respectively and n_(1) and n_(2) are the mole fractions of solvent and solute respectively. Then,

The vapour pressure of pure liquid solvent A is 0.80 atm . When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm , the mole fraction of component B in the solution is

The vapour pressure of a pure liquid A is 60 torr at 300K. It forms an ideal solution with another liquid B. The mole fraction of B is 0.25 and the total pressure of the solution is 82.5 torr at 300K. The vapour pressure of pure liquid B at 300K is

The vapour pressure of pure liquid solvent A is 0.80 atm.When a non volatile substances B is added to the solvent, its vapour pressure drops to 0.60 atm. Mole fraction of the components B in the solution is: