Let `f :R to R` be fefined as f(x) = 2x -1 and ` g : R - {1} to R` be defined as ` g(x) = (x-1/2)/(x-1)` Then the composition function ƒ(g(x)) is :

Let f:R rarr R be defined as f(x)=2x-1 and g:R-{1}rarr R be defined as g(x)=(x-(1)/(2))/(x-1) .Then the composition function f(g(x)) is :

Let f:R to be defined by f(x)=3x^(2)-5 and g : R to R by g(x)=(x)/(x^(2))+1 then gof is

Let f : R rarr R be defined by f(x) = x^(2) + 3x + 1 and g : R rarr R is defined by g(x) = 2x - 3, Find, (i) fog (ii) gof

Let f:R-{-1/2}toR and g:R-{-5/2}toR be defined as f(x)=(2x+3)/(2x+1) g(x)=(abs(x)+1)/(2x+5) then the domain of the function f(g(x) is:

Let f : R^+ ->R be defined as f(x)= x^2-x +2 and g : [1, 2]->[1,2] be defined as g(x) = [x]+1. Where [.] Fractional part function. If the domain and range of f(g(x)) are [a, b] and [c, d) then find the value of b/a + d/c.

If f:R to R be defined by f(x)=3x^(2)-5 and g: R to R by g(x)= (x)/(x^(2)+1). Then, gof is

Let f, g : R rarr R be defined respectively by f(x) = 2x + 3 and g(x) = x - 10. Find f-g.

If f:R rarr R is a function f(x)=x^(2)+2 and g:R rarr R is a function defined as g(x)=(x)/(x-1), then (i) fog (ii) go f