Find the area of the smaller part of the circle `x^(2) + y^(2) = a^(2)` cut off by the line `x = (a)/(sqrt(2))`.

Find the ara of the smaller part of the circle x ^(2) +y ^(2) =a ^(2) cut off by the line x = (a)/(sqrt2).

The area of the smaller part of the circle x^(2)+y^(2)=2 cut off by the line x=1 is

Prove that area of the smaller part of the cirlce x ^(2) + y ^(2) =a ^(2) cut off by the line x = (a)/(sqrt2) is (a ^(2))/( 4) (pi-2) sq. units.

The area of smaller portion of the circle x^(2)+y^(2)=a^(2) cut off by the line x=(a)/(2)(a>0) is

The area of the smaller portion of the circle x^(2)+y^(2)=4 cut off the line x+y=2 is

Find the area of the smaller portion of the circle x^2+y^2=4 cut off by the line x^2=1

" The area of the smaller portion of the circle "x^(2)+y^(2)=4" cut-off by the line "x=1" is "((n pi-3sqrt(3))/(3))m^(2)" .Find the value of "n" ."

The area of smaller part between the circle x^(2)+y^(2)=4 and the line x=1 is

The area of the smaller region bounded by the circle x^(2) + y^(2) =1 and the lines |y| = x +1 is

The area of the smaller segment cut off from the circle x^(2)+y^(2)=9 by x = 1 is