Prove that `|[265,240,219],[240,225,198],[219,198,181]|=0`

The value of Delta by using the properties of determinant where Delta = |{:(265,240,219),(240,225,198),(219,198,181):}| is

Evaluate |{:(265, 240, 219),(240, 225, 198), (219, 198, 181):}|

Find the values of the following determinants : (i) |{:(12,3,4),(16,5,0),(21,-1,2):}| (ii) |{:(256,240,219),(240,225,198),(219,198,181):}| (iii) |{:(17,19,24),(6,8,13),(-1,1,6):}| (iv) |{:(67,19,21),(39,13,14),(81,24,26):}| (v) |{:(1,omega,omega^(2)),(omega,omega^(2),1),(omega^(2),omega,1):}|" where "omega "is a cube root of unity". (iv) |{:(1,x,y),(0,(2pi)/5,sin(pi)/10),(0,sin((2pi)/5),cos(pi)/10):}|

|[225, 240, 189] , [210, 225, 204] , [212, 252, 188]|

Evaluate abs([2,4,0],[-1,1,2],[0,-2,1])

Prove that cos120^@cos240^@-sin120^@sin240^@=1

If cos theta=-1/2 and 0^@ < theta < 360^@ then the solutions are a. 60^@, 240^@, b.120^@, 240^@, c.120^@, 210^@, d.120^@, 300^@

The cofactor of 2 in the determinant [(3,4,-1),(2,4,0),(0,-2,1)] is: