If `[vec a xx vecb" "vecb xx vecc" "vecc xx veca]=lambda[veca vecb vecc]^2` then `lambda` is equal to

If [veca xx vecb vecb xx vecc vecc xx veca]=lambda[veca vecb vecc^(2)] , then lambda is equal to

If vecd = gamma(veca xx vecb) + mu(vecb xx vecc) + v(vecc xx veca) and [veca vecb vecc]=1/8 , then lambda = mu + v is equal to:

Let veca,vecb,vecc be three vectors such that veca ne vec0 and veca xx vecb=2veca xx vecc, |veca|=|vecc|=1,|vecb|=4 and |vecbxxvecc|=sqrt(15) . If vecb-2vecc=lambdaveca , then |lambda| is equal to :

if veca xx vecb = vecc.vecb xx vecc = veca , " where " vecc ne vec0 then

if veca xx vecb = vecc.vecb xx vecc = veca , " where " vecc ne vec0 then

Then for any arbitary vector veca, (((veca xx vecb) + (veca xx vecb))xx (vecb xx vecc)) (vecb -vecc) is always equal to

If veca + 2 vecb + 3 vecc = vec0 " then " veca xx vecb + vecb xx vecc + vecc xx veca=

For any four vectors veca, vecb, vecc, vecd the expressions (vecb xx vecc).(veca xx vecd) +(vecc xx veca).(vecb xx vecd)+(veca xx vecb).(vecc xx vecd) is always equal to: