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sin[cos^(-1)(3/5)]...

`sin[cos^(-1)(3/5)]`

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Evaluate sin[2cos^(-1)(-3/5)] .

sin{2\ cos^(-1)(-3/5)} is equal to 6//25 (b) 24//25 (c) 4//5 (d) -24//25

Prove that: tan^(-1)(63)/(16)=sin^(-1)(5)/(13)+cos^(-1)(3)/(5)

Prove that :tan^(-1)(63)/(16)=sin^(-1)(5)/(13)+cos^(-1)(3)/(5)

If "tan"^(-1)(x+1)+cot^(-1)(x-1)="sin"^(-1) (4/5) + cos^(-1) (3/5) , then x has the value:

If |z-25i|le15 , then |maximum arg(z) - minimum arg(z)| equals (A) (pi)/(2)+cos^(-1)((3)/(5)) (B) sin^(-1)((3)/(5))-cos^(-1)((3)/(5)) (C) 2cos^(-1)((4)/(5)) (D) 2cos^(-1)((1)/(5))

Prove that : cos^(-1).(3)/(5)+ cos^(-1).(12)/(13) = sin^(-1)((12)/(5))

cos[2cos^(-1).(1)/(5)+sin^(-1).(1)/(5)] =

sin^(-1)((5)/(13))+cos^(-1)((3)/(5))=

The value of sin[2"cos"^(-1)(sqrt(5))/(3)] is