`|(sin alpha, cos alpha, cos(alpha+delta)) ,(sin beta, cos beta , cos(beta +delta)),(sin gamma, cos gamma, cos (gamma+delta))|=0`

Prove that det [[sin alpha, cos alpha, sin (alpha + delta) sin beta, cos beta, sin (beta + delta) sin gamma, cos gamma, sin (gamma + delta)]] = 0

Without expanding,show that the value of each of the determinants is zero: det[[sin alpha,cos alpha,cos(alpha+delta)sin beta,cos beta,cos(beta+delta)sin gamma,cos gamma,cos(gamma+delta)]]

Without expanding evaluate the determinant |sin alpha cos alpha sin(alpha+delta)sin beta cos beta sin(beta+delta)sin gamma cos gamma sin(gamma+delta)|

|(sin alpha, cosalpha,sin(alpha+delta)),(sinbeta, cos beta,sin(beta+delta)),(singamma,cosgamma,sin(gamma+delta))|=

Without expanding evaluate the determinant det[[sin alpha,cos alpha sin(alpha+delta)sin beta,cos beta,sin(beta+delta)sin gamma,cos gamma,sin(gamma+delta)]]

If Delta=|(sin alpha, cos alpha, sin alpha+cos beta),(sin beta, cos alpha, sin beta+cos beta),(sin gamma, cos alpha, sin gamma+cos beta)| then Delta equals

Suppose alpha ,beta , gamma in R are such that sin alpha, sin beta , sin gamma ne 0 and Delta = |{:(sin^(2) alpha , sin alpha cos alpha , cos^(2) alpha),(sin^(2) beta , sin beta cos beta , cos^(2) beta),(sin^(2) gamma , sin gamma cos gamma , cos^(2) gamma):}| then Delta cannot exceed

If Delta = det [[sin alpha, cos alpha, sin alpha + cos alphasin beta, cos alpha, sin beta + cos betasin gamma, cos alpha, sin gamma + cos beta]] then Delta

If alpha,beta,gamma are real numbers,then determinant Delta=det[[sin^(2)alpha,cos2 alpha,cos^(2)alphasin^(2)beta,cos2 beta,cos^(2)betasin^(2)gamma,cos2 gamma,cos^(2)gamma]] equals

If cos (alpha + beta) sin (gamma + delta) = cos (alpha - beta) sin (gamma - delta) then: