Find the gravitational force of attraction between the ring and sphere as shown in the diagram, where the plane of the ring is perpendicular to the line joining the centres. If `sqrt8R` is the distance between the centres of a ring (of mass 'm') and a sphere (mass "M") where both have equal radius "R'

Find the force of attraction between a solid sphere of mass M and a ring of mass m as shown.

The gravitational force of attraction between a uniform sphere of mass M and a uniform rod of length l and mass in as shown in figure is

find the gravitational force of attraction between a uniform sphere of mass M and a uniform rod of length L and mass m, placed such that r is the distance between the centre of the sphere and the near end of the road.

The escape velocity form the centre of a unifrom ring of mass M and radius R is :

A ring of radius R having a linear charge density lambda moves towards a solid imaginary sphere of radius (R)/(2) , so that the centre of ring passes through the centre of sphere. The axis of the ring is perpendicular to the line joining the centres of the ring and the sphere. The maximum flux through the sphere in this process is

Find potential at a point 'P' at a distance 'x' on the axis away from centre of a uniform ring of mass M and radius R .

Find the intensity of gravitational field at a point lying at a distance x from the centre on the axis of a ring of radius a and mass M .

A particle of mass m is placed at a distance x from the centre of ring along the line through the centre of the ring and perpendicular to its plane. The force, when x=0 :

Find the force of attraction on a particle of mass m placed at the centre of a quarter ring of mass mand radius R as shown in figure.

Moment of inertia of a ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane is