A particle of mass (m) is attached to a spring (of spring constant k) and has a narural angular frequency omega_(0). An external force `R(t)` proportional to cos omegat(omega!=omega)(0) is applied to the oscillator. The time displacement of the oscillator will be proprtional to.

A particle of mass m is attached to three identical springs of spring constant k as shwon in figure. The time period of vertical oscillation of the particle is

A body of mass 1 kg oscillates on a spring of force constant 16 N/m. Calculate the angular frequency.

A body of mass 16 kg is made to oscillate on a spring of force constant 100 N kg^(-1) . Deduce the angular frequency.

If a body of mass 0.98 kg is made to oscillate on a spring of force constant 4.84 N/m the angular frequency of the body is

An object of mass m, oscillating on the end of a spring with spring constant k has amplitude A. its maximum speed is

When a particle of mass m is attached to a vertical spring of spring constant k and released, its motion is described by y (t) = y_0 sin^2omegat , where 'y' is measured from the lower end of unstretched spring. Then omega is :

A particle of mass m is fixed to one end of a massless spring of spring constant k and natural length l_(0) . The system is rotated about the other end of the spring with an angular velocity omega ub gravity-free space. The final length of spring is

A particle of mass m is attached with three springs A,B and C of equal force constancts k as shown in figure. The particle is pushed slightly against the spring C and released. Find the time period of oscillation. .

A small mass m attached to one end of a spring with a negligible mass and an unstretched length L, executes vertical oscillations with angular frequency omega_(0) . When the mass is rotated with an angular speed omega by holding the other end of the spring at a fixed point, the mass moves uniformly in a circular path in a horizontal plane. Then the increase in length of the spring during this rotation is