Mass `M` is split into two parts `m` and `(M-m)`, which are then separated by a certain distance. What is the ratio of `(m//M)` which maximises the gravitational force between the parts ?

A mass M splits into two parts m and (M - m) , which are then separated by a certain distance. Wha ratio (m/M) maximize the gravitational force between the path ?

A mass M is split into two parts m and (M-m) which are then separated by certain distance. Find ratio (m/M) to maximise the gravitational force F=(Gm(M-m))/(r^(2)) between the parts. Here G = gravitational constant and r is the distance between m and (M-m).

Mass M is divided into two parts m_1 , and m_2 , For a given separation the ratio of m_1/M for which the gravitational attraction between the two parts becomes maximum is

A body of mass (2M) splits into four masses {m,M-m,m,M-m} , which are rearranged to form a square as shown in the figure. The ratio of (M)/(m) for which, the gravitational potential energy of the system becomes maximum is x : 1 . The value of x is ________.

Two spheres of masses (m) and (M - m) are prepared from a sphere of mass M. They are kept at a distance x. For what ratio of (m)/(M) will the gravitational attraction between them be maximum ?

A particle of mass m is located inside a spherical shell of mass M and radius R. The gravitational force of attraction between them is

Two bodies of masses M_(1) and M_(2) are kept separeated by a distance d. The potential at the point where the gravitational field produced by them is zero, is :-