`int(sinx dx)/(sin(x-alpha)`

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If int (sin x)/(sin (x-alpha))dx =Ax+B log sin (x-alpha)+C , then the value of (A,B) , is

If int(sin x)/(sin(x-alpha))dx=Ax+B log sin(x-alpha) , then value of (A,B) is

int(sin x)/(sin(x+alpha)dx)

int(sinx+cosx)/(sin(x+alpha))dx=

int(sinx)/(sin(x-alpha)) dx = ?

Evaluate : int(sinx)/(sin(x-alpha))dx .

If int(sinx)/(sin(x-alpha))dx=Ax+Blogsin(x-alpha)+c then

int(sin2x)/(sin(x-alpha)sin(x+alpha))dx

int(sin x+cos x)/(sin(x -alpha))dx is equal to