Solve: `z +2barz=ibarz`

Solve for z: z^2 = (ibarz)^2 .

Show that the equation of the circle in the complex plane with z_1 & z_2 as its diameter can be expressed as , 2z barz-(barz_1+barz_2)z-(barz_1+barz_2)barz+z_1barz_2+z_2barz_1=0

Solve :z^(2)+|z|=0

If z=ibarz then

If z_1=7+3i and z_2=-7+3i then find the following: barz_1barz_2

If z_1=7+3i and z_2=-7+3i then find the following: barz_1/barz_2

If a point z_(1) is the reflection of a point z_(2) through the line b barz+barbz=c, b in 0 , in the Argand plane, then b barz_(2)+ barb z_(1)=

If |z+barz|=|z-barz| , then value of locus of z is

if z=3 -2i, then verify that (i) z + barz = 2Rez (ii) z - barz = 2ilm z

If |z_(1)|=|z_(2)|=|z_(3)|=1 and z_(1)+z_(2)+z_(3)=sqrt(2)+i , then the complex number z_(2)barz_(3)+z_(3)barz_(1)+z_(1)barz_(2) , is