`(log)_3(1+1/3)+(log)_3(1+1/4)+(log)_3(1+1/5)+ddot+(log)_3(1+1/(242))` when simplified has the value equal to: 2 (b) 4 (c) 6 (d) `(log)_2 16`

log_(3)(1+(1)/(3))+log_(3)(1+(1)/(4))+log_(3)(1+(1)/(5))+...+log_(3)(1+(1)/(242)) when simplified has the value equal to: 2 (b) 4 (c) 6 (d) log _(2)16

log_(3)(1-(1)/(3))+log_(3)(1+(1)/(4))+log_(3)(1+(1)/(5))+...+log_(3)(1+(1)/(242)) when simplified has the value equal to: 2 b.4c.6d.log_(2)16

(log_(2)3)(log_(1/3)5)(log_(4)6)<1

If log_(10)(x-1)^(3)-3log_(10)8(x-3)=log_(10)8 then log_(x)625 has the value of equal to: 5(b)4 (c) 3 (d) 2

(log)_(2)(log)_(2)(log)_(3)(log)_(3)27^(3) is 0 b.1 c.2 d.3

((log)_(2)3)(log)_(3)4(log)_(4)5(log)_(n)(n+1)=10 Find n=?

If xy^(2) = 4 and log_(3) (log_(2) x) + log_(1//3) (log_(1//2) y)=1 , then x equals

((log)_(5)5)((log)_(4)9)((log)_(3)2) is equal to 2 b.5 c.1 d.(3)/(2)

The expression (1)/(log_(5)3)+(1)/(log_(6)3)-(1)/(log_(10)3) simplifies to

The number N=(1+2log_(3)2)/((1+log_(3)2)^(2))+(log_(6)2)^(2) when simplified reduces to: