Two sides of a parallelogram are along the lines `x+y=3` and `x-y+3=0` .If its diagonal intersect at `(2,4)` then one of its vertex is

Two sides of a parallelogram are along the lines x+y=3 and x=y+3. If its diagonals intersect at (2, 4) , then one of its vertices is

Two sides of a rhombus are along the lines,x-y+1=0 and 7x-y-5=0 .If its diagonals intersect at (-1,-2) ,then which one of the following is a vertex of this rhombus?

Two sides of a parallelogram are x+y=3 and y-x=3. If the diagonals meet at (2,4) then which of the following can be one of the vertex of parallelogram.(a) (3,6)(b)(0,0)(c)(1,-2)(d)(2,3)

Two sides of a Rhombus ABCD are parallel to the lines x-y=5 and 7x-y=3. The diagonals intersect at (2,1) then the equations of the diagonals are

Two sides of a parallelogram are along the lines 4x + 5y = 0 and 7x + 2y = 0. If the equation of one of the diagonals of the parallelogram is 11x + 7y = 9, then other diagonal passes through the point :

The sides of a parallelogram are parallel to the lines 5x-y=0 and 7x+y=0. If (1,3) and (-2,4) are a pair of its opposite vertices find the equations of all of its sides.

Two sides of a square lie on the lines x + y = 1 and x + y + 2 = 0. What is its area?

The diagonals of a parallelogram PQRS are along the lines x+3y=4 and 6x-2y=7, Then PQRS must be: