The mean and variance of a binomial distribution are 30 and 5, respectively. Then probability of two successes is

Mean and variance of a binomial distribution are 4 and 2 respectively . Then probability of 3 successes is

The mean and the variance of a binomial distribution are 4 and 2 respectively.Then the probability of 3 successes is

The mean and variance of a binomial distribution are 6 and 4 respectively, then n is

The mean and the variance of a binomial distribution are 4 and 2 respectively. Then, the probability of 2 successes is

The mean and the variance of a binomial distribution are 4 and 2 respectively.then, the probabitly of 2 , successes is

The mean and variance of a binomial distribution are 4 and 3 respectively. Then the probability of getting exacatly six successes in this distribution, is

The mean and varaince of binomial distribution are 4 and 3, respectively. Then, the probability of getting exactly six success in this distribution is

If the mean and variance of a binomial distribution are 9 and 6 respectively , then n = …..

The mean and variance of a binomial distribution are 4 and 4/3 respectively, find P(Xgeq1)dot