Two particles A and B with particle A having mass m, are moving towards each other under their mutual force of attraction. If their speeds at certain instant are v and 2v respectively, then find the K.E. of the system.

Two paricle A and B initially at rest, move towards each other under mutual force of attraction. At the instant when the speed of A is V and the speed of B is 2V, the speed of the centre of mass of the system is

Two partticles A and B intially at rest move towards each other under a mutual force of attraction. The instant at which velocity of A is 4v and velocity of B is 2v , the velocity of centre of mass of the system at that instant will be

Two particles of masses 4kg and 6kg are separated by a distance of 20cm and are moving towards each other under mutual force of attraction, the position of the point where they meet is

Two particles A and B initially at rest, move towards each other, under mutual force of attraction. At an instance when the speed of A is v and speed of B is 2v , the speed of centre of mass ( CM ) is

Two particles of mass m_(1) and m_(2) are approaching towards each other under their mutual gravitational field. If the speed of the particle is v, the speed of the center of mass of the system is equal to :

10 Two particles of masses m_(1) and m_(2) initially at rest start moving towards each other under their mutual force of attraction. The speed of the centre of mass at any time t, when they are at a distance r apart, is

Two particle which are initially at rest move towards each other under the action of their internal attraction. If their speeds are v and 2 v at any instant, then the speed of centre of mass of the system will be