Three particles P, Q and R
are situated at point A on the circular path of radius 10m. All three particles move along different path and reach at point B shown in figure. Then the ratio of distance traversed by particle P and Q is:-

A particle moves along on a road with constant speed at all points as shown in figure. The normal reaction of the road on the particle is :

A particle moves along a path ABCD as shown in the figure. Then the magnitude of net displacement of the particle from position A to D is:

The speed-time graph of a particle moving along a fixed direction as shown in the figure. The distance traversed by the particle between t = 0 s to t = 10 s is

Two particles A and B are present at centre (O) of circle of a radius (R) as shown in figure. Particle A moves along path OPQ and reach at point Q in 2 sec. Another particle B moves along path ORPQ reach at Q in 5 sec., then ratio of average velocity of A to B -

A particle moves from A to B in a circular path of radius R covering an angle theta as shown in figure. Find the ratio of magnitude of distance and magnitude of displacement of the particle.

A particle of mass 'm' is moving on a circular path of radius 'r' with uniform speed 'v'. Rate of change of linear momentum is

A particle of mass m is moving on a circular path of radius r with uniform speed v , rate of change of linear momentum is

A particle of mass M moves with constant speed along a circular path of radius r under the action of a force F. Its speed is

A particle is moving along a circular track of radius r. What is the distance traversed by particle in half revolution ? What is its displacement ?