A wave has SHM (simple harmonic motion) whose period is 4s while another periods 3 s. If both are combined, then the resultant wave will have the period equal to

Simple pendulum is executing simple harmonic motion with time period T . If the length of the pendulum is increased by 21% , then the increase in the time period of the pendulum of the increased length is:

What is meant by simple harmonic motion (S.H.M.) ?

A particle at the end of a spring executes simple harmonic motion with a period t_1 , while the corresponding period of another spring is t_2 . If the period of oscillation with the two springs in series is T. Then

A particle executing simple harmonic motion with time period T. the time period with which its kinetic energy oscilltes is

If particle is excuting simple harmonic motion with time period T, then the time period of its total mechanical energy is :-

A simple pendulum is executing simple harmonic motion with a time period T. If the length of the pendulum is increased by 21%, the percentage increase in the time period of the pendulum of is

A simple harmonic motion has an amplitude A and time period T. What is the time taken to travel from x=A to x=A//2 ?

A simple harmonic motino has amplitude A and time period T. The maxmum velocity will be

A particle performing simple harmonic motion having time period 3 s is in phase with another particle which also undergoes simple harmonic motion at t=0 . The time period of second particle is T (less that 3s). If they are again in the same phase for the third time after 45 s, then the value of T will be