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Find the square root of : 0.007225...

Find the square root of :
`0.007225`

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To find the square root of \(0.007225\), we can use the long division method for square roots. Here’s a step-by-step solution: ### Step 1: Pair the digits Start by pairing the digits of the number from the decimal point. For \(0.007225\), we can pair it as follows: - \(00 | 72 | 25\) ### Step 2: Find the largest square Now, we look for the largest square less than or equal to the first pair, which is \(00\). - The largest square less than or equal to \(0\) is \(0\) (since \(0^2 = 0\)). - Write \(0\) above the line. ### Step 3: Subtract and bring down the next pair Subtract \(0\) from \(00\) which gives \(0\). Now, bring down the next pair \(72\): - Current value: \(00 - 00 = 00\) - Bring down \(72\) to get \(72\). ### Step 4: Find the next digit Now, we need to find a digit \(x\) such that \(2 \cdot 0 \cdot x + x^2 \leq 72\). - Trying \(8\): \(2 \cdot 0 \cdot 8 + 8^2 = 64\) (which is less than \(72\)). - Write \(8\) above the line. ### Step 5: Subtract again Now, subtract \(64\) from \(72\): - \(72 - 64 = 8\). - Bring down the next pair \(25\) to get \(825\). ### Step 6: Find the next digit Now, we need to find a digit \(y\) such that \(2 \cdot 8 \cdot y + y^2 \leq 825\). - \(2 \cdot 8 = 16\), so we need \(16y + y^2 \leq 825\). - Trying \(5\): \(16 \cdot 5 + 5^2 = 80 + 25 = 105\) (which is less than \(825\)). - Write \(5\) above the line. ### Step 7: Final subtraction Now, subtract \(825\) from \(825\): - \(825 - 825 = 0\). ### Conclusion Since we have reached \(0\) with no remainder, the square root of \(0.007225\) is \(0.085\). ### Final Answer \[ \sqrt{0.007225} = 0.085 \]
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ICSE-SQUARES AND SQUARE ROOTS-Exercise3 (B)
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