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Find the numbers whose : (ii) product `= 6` and sum `= - 5`

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To find the numbers whose product is 6 and sum is -5, we can follow these steps: ### Step 1: Set up the equations Let the two numbers be \( x \) and \( y \). We know: 1. \( x \cdot y = 6 \) (Product) 2. \( x + y = -5 \) (Sum) ### Step 2: Express one variable in terms of the other From the product equation, we can express \( x \) in terms of \( y \): \[ x = \frac{6}{y} \] ### Step 3: Substitute into the sum equation Substituting \( x \) into the sum equation gives: \[ \frac{6}{y} + y = -5 \] ### Step 4: Clear the fraction To eliminate the fraction, multiply the entire equation by \( y \) (assuming \( y \neq 0 \)): \[ 6 + y^2 = -5y \] ### Step 5: Rearrange into standard quadratic form Rearranging the equation gives: \[ y^2 + 5y + 6 = 0 \] ### Step 6: Factor the quadratic equation Now, we need to factor the quadratic equation: \[ y^2 + 5y + 6 = (y + 2)(y + 3) = 0 \] ### Step 7: Solve for \( y \) Setting each factor to zero gives: 1. \( y + 2 = 0 \) → \( y = -2 \) 2. \( y + 3 = 0 \) → \( y = -3 \) ### Step 8: Find corresponding \( x \) values Now, we can find the corresponding \( x \) values using \( x = \frac{6}{y} \): - If \( y = -2 \): \[ x = \frac{6}{-2} = -3 \] - If \( y = -3 \): \[ x = \frac{6}{-3} = -2 \] ### Conclusion Thus, the two numbers are \( -2 \) and \( -3 \). ---
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