A die is thrown, find the probability of getting:
a number not greater than 4

Answer

To find the probability of getting a number not greater than 4 when a die is thrown, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Total Outcomes**:
When a die is thrown, the possible outcomes are the numbers 1, 2, 3, 4, 5, and 6.
- **Total Outcomes = 6**

2. **Identify the Favorable Outcomes**:
We need to find the outcomes that are not greater than 4. The numbers that satisfy this condition are 1, 2, 3, and 4.
- **Favorable Outcomes = 1, 2, 3, 4**
- **Count of Favorable Outcomes = 4**

3. **Calculate the Probability**:
Probability is calculated using the formula:
\[ \text{Probability} = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Outcomes}} \]
Substituting the values we found:
\[ \text{Probability} = \frac{4}{6} \]

4. **Simplify the Fraction**:
We can simplify \(\frac{4}{6}\) by dividing both the numerator and the denominator by their greatest common divisor, which is 2.
\[ \frac{4 \div 2}{6 \div 2} = \frac{2}{3} \]

5. **Final Answer**:
The probability of getting a number not greater than 4 when a die is thrown is:
\[ \frac{2}{3} \]