In a single throw of a die, find the probability of getting:
a number greater than 8

Answer

To solve the problem of finding the probability of getting a number greater than 8 in a single throw of a die, we can follow these steps:

### Step 1: Identify the possible outcomes when throwing a die.
When you throw a standard six-sided die, the possible outcomes are:
- 1
- 2
- 3
- 4
- 5
- 6

### Step 2: Determine the total number of possible outcomes.
The total number of possible outcomes when throwing a die is 6.

### Step 3: Identify the favorable outcomes for the event "number greater than 8."
We need to find the outcomes that are greater than 8. However, the highest number on a standard die is 6. Therefore, there are no outcomes that are greater than 8.

### Step 4: Calculate the number of favorable outcomes.
Since there are no outcomes greater than 8, the number of favorable outcomes is 0.

### Step 5: Use the probability formula.
The probability \( P \) of an event is given by the formula:
\[ P(\text{Event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \]
Substituting the values we found:
\[ P(\text{Number greater than 8}) = \frac{0}{6} = 0 \]

### Conclusion:
The probability of getting a number greater than 8 when throwing a die is 0.

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