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Three identical coins are tossed togethe...

Three identical coins are tossed together. What is the probabilit of obtaining:
no head?

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To find the probability of obtaining no heads when three identical coins are tossed, we can follow these steps: ### Step 1: Determine the total number of outcomes When three coins are tossed, each coin has 2 possible outcomes: heads (H) or tails (T). Therefore, the total number of outcomes when tossing three coins can be calculated as: \[ \text{Total outcomes} = 2^n \] where \( n \) is the number of coins. In this case, \( n = 3 \): \[ \text{Total outcomes} = 2^3 = 8 \] ### Step 2: List all possible outcomes The possible outcomes when tossing three coins are: 1. HHH (3 heads) 2. HHT (2 heads, 1 tail) 3. HTH (2 heads, 1 tail) 4. THH (2 heads, 1 tail) 5. HTT (1 head, 2 tails) 6. THT (1 head, 2 tails) 7. TTH (1 head, 2 tails) 8. TTT (0 heads, 3 tails) ### Step 3: Identify favorable outcomes for no heads We need to find the outcomes that result in no heads. From the list above, the only outcome that has no heads is: - TTT (0 heads) Thus, the number of favorable outcomes for obtaining no heads is: \[ \text{Favorable outcomes} = 1 \] ### Step 4: Calculate the probability The probability of an event is given by the formula: \[ \text{Probability} = \frac{\text{Favorable outcomes}}{\text{Total outcomes}} \] Substituting the values we found: \[ \text{Probability of no heads} = \frac{1}{8} \] ### Final Answer The probability of obtaining no heads when three identical coins are tossed is: \[ \frac{1}{8} \] ---
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ICSE-PROBABILITY-Exercise
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