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From 10 identical cards, numbered 1,2,3,...

From `10` identical cards, numbered `1,2,3,…., 10` one card is drawn at random. Find the probability that the number on the card drawn is a multiple of:
`2` and `3`

A

`(1)/(10)`

B

`(3)/(10)`

C

`(1)/(11)`

D

`(1)/(7)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the probability that the number on the card drawn is a multiple of both `2` and `3`, we can follow these steps: ### Step 1: Identify the Total Number of Outcomes The total number of outcomes is the total number of cards available. Since the cards are numbered from `1` to `10`, the total number of outcomes is: \[ \text{Total Outcomes} = 10 \] ### Step 2: Identify the Multiples of 2 and 3 Next, we need to find the numbers between `1` and `10` that are multiples of both `2` and `3`. The least common multiple (LCM) of `2` and `3` is `6`. Now, we will check the multiples of `6` within the range of `1` to `10`: - The multiples of `6` are: `6` ### Step 3: Count the Favorable Outcomes From the previous step, we see that there is only one number (`6`) that is a multiple of both `2` and `3`. Therefore, the number of favorable outcomes is: \[ \text{Favorable Outcomes} = 1 \] ### Step 4: Calculate the Probability The probability \( P \) of drawing a card that is a multiple of both `2` and `3` is given by the formula: \[ P = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Outcomes}} = \frac{1}{10} \] ### Final Answer Thus, the probability that the number on the card drawn is a multiple of `2` and `3` is: \[ \boxed{\frac{1}{10}} \] ---
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