A die is thrown once. Find the probability of getting:
a number greater than 3

Answer

To find the probability of getting a number greater than 3 when a die is thrown once, we can follow these steps:

### Step 1: Identify the total number of possible outcomes.
When a die is thrown, the possible outcomes are the numbers on the faces of the die, which are:
1, 2, 3, 4, 5, 6.

**Total possible outcomes = 6.**

**Hint:** Count the number of faces on the die to determine the total outcomes.

### Step 2: Identify the favorable outcomes.
We need to find the outcomes that are greater than 3. The numbers greater than 3 on a die are:
4, 5, and 6.

**Favorable outcomes = 4, 5, 6.**

**Hint:** List the numbers on the die and select those that meet the condition (greater than 3).

### Step 3: Count the number of favorable outcomes.
From the previous step, we see that there are 3 favorable outcomes (4, 5, and 6).

**Number of favorable outcomes = 3.**

**Hint:** Simply count how many numbers you identified in the previous step.

### Step 4: Calculate the probability.
The probability (P) of an event is given by the formula:
\[ P(\text{event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \]

Substituting the values we found:
\[ P(\text{number greater than 3}) = \frac{3}{6} \]

### Step 5: Simplify the fraction.
Now, we can simplify \( \frac{3}{6} \):
\[ \frac{3}{6} = \frac{1}{2} \]

### Final Answer:
The probability of getting a number greater than 3 when a die is thrown once is \( \frac{1}{2} \).

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