On the basis of molecular weights of `NaOH` and `H_2O`, which is heavier?

Calculate the formula weight of compounds NaOH

The equivalent weights of oxidising and reducing agents can be calculated by the number of electrons gained or lost. The equivalent weight of an oxidising agent is the number of parts by weight of the substance which gains one electron. Thus, it is equal to the molecular weight of the substance divided by the number of electrons gained in the balanced chemical equation. Similarly, equivalent weight of a reducing agent is equal to the molecular weight divided by the number of electrons lost as represented in the balanced chemical equation The equivalent weght of As_(2),S_3 in the following reaction As_(2)S_(3) + H^(+) + NO_(3)^(-) rarr NO + H_(2)O + AsO_(4)^(3-) + SO_(4)^(2-) is related to its molecular weight as

Which of the following acid has the same molecular weight and equivalent weight ?

(A) : Water has more boiling point than that of hydrgen fluoride. (R): The molecular weight of H_2 O is more than HF

(A) The boiling point of C_2H_5OH is less than that of H_2O , though the molecular weight of C,H,OH is more than that of water. (R) C_2H_5OH molecules are not highly associated through hydrogen bonding as in water.

M' is the molecular weight of KMnO_4 The equivalent weight of KMnO_4 when it reacts according to the equation 2KMnO_4 + 3H_2SO_4 + 5H_2C_2O_4 to K_2SO_4 + 2MnSO_4 + 8H_2O + 10CO_2

Write the structures of the alcohols with the molecular formula, C_5H12O which exhibit enantiomorphism.