`(e^y+1)cosx dx+e^ysinx dy=0`

Find the general solution of each of the following differential equations: (e^(y)+1)cosx dx +e^(y)sinx dy =0

The solution of e^(x-y) dx + e^(y-x) dy = 0 is

If y=(e^(2x)cosx)/(x sinx),then(dy)/(dx) =

If y=(e^(2x)cosx)/(x sinx),then(dy)/(dx) =

e^(x-y)(sinx+cosx)dx+(cosy-siny)dy=0

Find dy/dx for (x+y)^(cosx) = e^(x+y) .