Home
Class 12
PHYSICS
A satellite of mass m is launched vertic...

A satellite of mass m is launched vertically upwards with an initial speed U from the surface of the Earth. After it reaches height 2 R (R = radius of Earth) it ejects a rocket of mass `(m)/(5)` So, that subsequently the satellite moves in a circular orbit. The kinetic energy of rocket is (M is mass of Earth)

Promotional Banner

Similar Questions

Explore conceptually related problems

A satellite of mass m is launched vertically upwards with initial kinetic energy K from the Earth’s surface. After it reaches height R (R = radius of earth). It ejects a rocket of mass m/5 so that subsequently the satellite moves in a circular orbit. The kinetic energy of rocket is [G is gravitational constant, M is the mass of the earth, take (GMm)/(R)=K ]

A satellite of mass m is launched vertically upwards with an initial speed sqrt((GM)/®) from the surface of the earth. After it reaches height R (R = radius of the earth), it ejects a rocket of mass m/10 in a direction opposite to the initial direction of the satellite, so that subsequently the satellite escapes to infinity. The minimum kinetic energy of the rocket at ejection needed is (G is the gravitational constant, M is the mass of the earth):

A satellite of mass 'M' is projected radially from surface of earth with speed 'u'. When is reaches a height equal to radius of earth, it ejects a rocket of mass ( M)/(10 ) and it itself starts orbiting the earth in circular path of radius 2R, find the kinetic energy of rocket.

A satellite of mass m moves around the Earth in a circular orbit with speed v. The potential energy of the satellite is

A satellite of mass m_0 is revolving around the earth in circular orbit at a height of 3R from surface of the earth the areal velocity of satellite is (where R is radius of earth and M_0 is the mass of earth)

A satellite of mass m is placed at a distance r from the centre of earth (mass M ). The mechanical energy of the satellite is

A satellite of mass m is orbiting the earth at a height h from its surface. If M is the mass of the earth and R its radius, the kinetic energy of the stellite will be

A satellite of mass m is revolving around the Earth at a height R above the surface of the Earth. If g is the gravitational intensity at the Earth’s surface and R is the radius of the Earth, then the kinetic energy of the satellite will be:

A satellite moves around the earth in a circular orbit with speed v . If m is the mass of the satellite, its total energy is