The mode for the table is
Class: 0-6, 6-12, 12-18, 18-24, 24-30
Frequency: 8, 10, 15, 5, 6 respectively

Find the mean deviation about the median of the following frequency distribution: Class: 0 - 6,6-12,12-18,18-24,24-30 Frequency: 8,10,12,9,5

Find the mean of the following frequency distributions: Class interval: 0-6 6-12 12-18 18-24 24-30 Frequency: 7 5 10 12 6

Find the mean of the following frequency distributions: Class interval: 0-6 6-12 12-18 18-24 24-30 Frequency: 6 8 10 9 7

Consider the following frequency distribution : {:("Class :",0-6,6-12,12-18,18-24,24-30),("Frequency : ",a,b,12,9,5):} If mean = (309)/(22) and median = 14, then the value (a-b)^(2) is equal to __________ .

For the following grouped frequency distribution find the mode: Class: 3-6,6-9,9-12,12-15,15-18,18-21,21-24 Frequency: 25,10,23,12,3

The upper limit of the median class of the following frequency distribution. {:("Class",0-5,6-11,12-17,18-23,24-29),("Frequency",13,10,15,8,11):}

Find the mean of the following frequency distributions: Class interval: 0-8 8-16 16-24 24-32 32-40 Frequency: 6 7 10 8 9

If x lt 6 and 17.5 is the mode of the following frequency distribution. {:("Class-interval:", 0-5,5-10,10-15,15-20,20-25),("Frequency:", 5,2,3,6,x):} Then, x =

Construct a frequency polygon for the following data: Age (in year) 0-2 2-4 4-6 4-8 8-10 10-12 12-14 14-16 16-18 Frequency 2 4 6 8 9 6 5 3 1