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A parallelogram has three consecutive v...

A parallelogram has three consecutive vertices (-3, 4), (0, -4) and (5,2). The fourth vertex is

A

(2, 10)

B

(2, 9)

C

(3, 9)

D

(4, 10)

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The correct Answer is:
To find the fourth vertex of the parallelogram given three consecutive vertices, we can follow these steps: ### Step 1: Identify the given vertices Let the three consecutive vertices of the parallelogram be: - \( A(-3, 4) \) - \( B(0, -4) \) - \( C(5, 2) \) ### Step 2: Use the midpoint formula In a parallelogram, the diagonals bisect each other. Therefore, the midpoint of diagonal \( AC \) should equal the midpoint of diagonal \( BD \) (where \( D \) is the fourth vertex we need to find). The midpoint \( O \) of diagonal \( AC \) can be calculated using the midpoint formula: \[ O = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \] where \( A(x_1, y_1) \) and \( C(x_2, y_2) \). Substituting the coordinates of \( A \) and \( C \): \[ O = \left( \frac{-3 + 5}{2}, \frac{4 + 2}{2} \right) = \left( \frac{2}{2}, \frac{6}{2} \right) = (1, 3) \] ### Step 3: Set up the equation for the midpoint of diagonal \( BD \) Let \( D \) have coordinates \( (x, y) \). The midpoint \( O \) of diagonal \( BD \) is given by: \[ O = \left( \frac{0 + x}{2}, \frac{-4 + y}{2} \right) \] Setting this equal to the midpoint we found earlier: \[ \left( \frac{0 + x}{2}, \frac{-4 + y}{2} \right) = (1, 3) \] ### Step 4: Solve for \( x \) and \( y \) From the first coordinate: \[ \frac{x}{2} = 1 \implies x = 2 \] From the second coordinate: \[ \frac{-4 + y}{2} = 3 \implies -4 + y = 6 \implies y = 10 \] ### Step 5: Conclusion Thus, the coordinates of the fourth vertex \( D \) are: \[ D(2, 10) \] ### Final Answer The fourth vertex of the parallelogram is \( (2, 10) \). ---
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