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Consider the following statements in res...

Consider the following statements in respect of the function f(x) = sinx :
1. f(x) increases in the interval `(0, pi)`.
2. f(x) decreases in the interval `((5pi)/(2), 3pi)`.
Which of the above statements is/are correct?

A

1 only

B

2 only

C

Both 1 and 2

D

Neither 1 nor 2

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correctness of the statements regarding the function \( f(x) = \sin x \), we will analyze the behavior of the sine function in the specified intervals. ### Step 1: Analyze the first statement **Statement 1:** \( f(x) \) increases in the interval \( (0, \pi) \). To check if \( f(x) = \sin x \) is increasing in the interval \( (0, \pi) \), we need to find the derivative of \( f(x) \). \[ f'(x) = \cos x \] Now, we evaluate the derivative in the interval \( (0, \pi) \): - At \( x = 0 \), \( f'(0) = \cos(0) = 1 \) (positive) - At \( x = \frac{\pi}{2} \), \( f'(\frac{\pi}{2}) = \cos(\frac{\pi}{2}) = 0 \) - At \( x = \pi \), \( f'(\pi) = \cos(\pi) = -1 \) (negative) Since \( f'(x) \) is positive in \( (0, \frac{\pi}{2}) \) and becomes zero at \( \frac{\pi}{2} \) and then negative in \( (\frac{\pi}{2}, \pi) \), we conclude that \( f(x) \) increases from \( 0 \) to \( \frac{\pi}{2} \) and then decreases from \( \frac{\pi}{2} \) to \( \pi \). Therefore, the statement that \( f(x) \) increases in the entire interval \( (0, \pi) \) is **incorrect**. ### Step 2: Analyze the second statement **Statement 2:** \( f(x) \) decreases in the interval \( \left(\frac{5\pi}{2}, 3\pi\right) \). Now, we check the behavior of \( f(x) \) in the interval \( \left(\frac{5\pi}{2}, 3\pi\right) \). - The critical points of \( \sin x \) occur at \( \frac{5\pi}{2} \) and \( 3\pi \). - At \( x = \frac{5\pi}{2} \), \( f'(\frac{5\pi}{2}) = \cos(\frac{5\pi}{2}) = 0 \) (point of inflection) - At \( x = 3\pi \), \( f'(3\pi) = \cos(3\pi) = -1 \) (negative) To determine the behavior in the interval \( \left(\frac{5\pi}{2}, 3\pi\right) \): - In this interval, \( f'(x) \) is negative (since \( \cos x \) is negative for \( x \) in \( \left(\frac{5\pi}{2}, 3\pi\right) \)). - Therefore, \( f(x) \) is indeed decreasing in this interval. Thus, the second statement is **correct**. ### Conclusion - Statement 1 is **incorrect**. - Statement 2 is **correct**. ### Final Answer Only statement 2 is correct. ---
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