Find the electric field at point P (as shown in figure) on the perpendicular bisector of a uniformly charged thin wire of length L carrying a charge Q. The distance of the point P from the centre of the rod is a `=sqrt3/2L`.

Find the electric field at a point P on the perpendicular bisector of a uniformly charged rod. The lengthof the rod is L, the charge on it is Q and the distance of P from the centre of the rod is a.

The electric foield at a point A on the perpendicular bisector of a uniformly charged wire of length l=3m and total charge q = 5 nC is x V/m. The distance of A from the centre of the wire is b = 2m. Find the value of x.

Calculate the potential at a point on the perpendicular bisector of uniformly charged thin rod (linear density of charge = lambda ) of length 2l at a distance a from the centre of the rod.

Find the magnetic field at a point P on the perpendicular bisector of the current carrying conductor :-

The electric field at a point P which is at a distance l on the perpendicular bisector of a uniformly charged wire of length 1 , charge Q=(Q)/(2 pi varepsilon_(0)l^(2)sqrt(k)) where k = ?

Find : (i)Electric field intensity due to an infinitely long uniformly charged, straight conductor , at a perpendicular distance d from rod. (ii)Electric field intensity at a point on perpendicular bisector of uniformly charged rod of length l and charge Q at a distance d from the centre of rod.

Electric field at a point of distance r from a uniformly charged wire of infinite length having linear charge density lambda is directly proportional to

Calculate the potential due to a thin uniformly charged rod of length L at the poiot P shown in figure. The lioear charge density of the rod is lambda C//m

A thin uniform rod of length L is bent at its mid point as shown in the figure. The distance of the centre of mass from the point O is