Find the product of :
`7pqr and 6p^(2)r^(2)`

Answer

To find the product of \( 7pqr \) and \( 6p^2r^2 \), we will follow these steps:

### Step 1: Multiply the numerical coefficients
First, we will multiply the numerical coefficients (the numbers in front of the variables):
\[ 7 \times 6 = 42 \]

### Step 2: Multiply the variables
Next, we will multiply the variables. We will handle each variable separately.

#### For \( p \):
- The first expression has \( p^1 \) (since \( p \) is the same as \( p^1 \)).
- The second expression has \( p^2 \).
- When multiplying like bases, we add the exponents:
\[ 1 + 2 = 3 \]
So, we have \( p^3 \).

#### For \( q \):
- The first expression has \( q^1 \).
- The second expression does not have \( q \) (which can be considered as \( q^0 \)).
- When multiplying, we add the exponents:
\[ 1 + 0 = 1 \]
So, we have \( q^1 \) or simply \( q \).

#### For \( r \):
- The first expression has \( r^1 \).
- The second expression has \( r^2 \).
- Again, we add the exponents:
\[ 1 + 2 = 3 \]
So, we have \( r^3 \).

### Step 3: Combine all parts
Now, we combine all the parts we calculated:
\[ 42p^3qr^3 \]

### Final Answer
Thus, the product of \( 7pqr \) and \( 6p^2r^2 \) is:
\[ \boxed{42p^3qr^3} \]