Take away `5m + 4n - 3mn " from " 7m - 2n + 5mn`

Find the angle between the lines whose direction-cosines are give l + 2m + 3n = 0 and 3lm - 4ln + mn = 0

Draw a line MN=5.8 cm. locate a point A which is 4.5 cm from M and 5 cm from N. through A draw a line parallel to line MN.

Find the angle between the lines whose direction cosines are given by the equations 3l + m + 5n = 0 and 6mn - 2nl + 5lm = 0

The direction cosines of two lines satisfying the conditions l + m + n = 0 and 3lm - 5mn + 2nl = 0 where l, m, n are the direction cosines. The value of lm+mn + nl is

The direction cosines of two lines satisfying the conditions l + m + n = 0 and 3lm - 5mn + 2nl = 0 where l, m, n are the direction cosines. Angle between the lines is

Subtract the sum of 3l-4m-7n^2a n d\ 2l+3m-4n^2 from the sum of 9l+2m-3n^2 and -3l+m+4n^2dot

If tan A + sin A = m and tan A - sin A = n, prove that : m^(2) - n^(2) = 4 sqrt (mn)

Find the greatest angle of DeltaABC if : a=m, b = n, c = sqrt(m^2 + mn + n^2)

Find the value of m and n : if : ( 5+ 2sqrt3)/( 7+ 4sqrt3) = m + n sqrt3

If m : n is the duplicate ratio of (m + x) :( n + x) , show that: x^2=mn