A compound has the following percentage composition by mass : Carbon = 54.55%, Hydrogen = 9.09% and Oxygen = 36.26%.
Its vapour density is 44. Find the Empirical and molecular formula of the compound.
(H = 1, C = 12,0 = 16)

Explanation

To solve the problem, we will follow these steps:

### Step 1: Assume a Sample Size
Assume we have 100 grams of the compound. This simplifies the calculation of moles based on the percentage composition.

### Step 2: Determine the Mass of Each Element
From the percentage composition:
- Carbon (C) = 54.55% of 100 g = 54.55 g
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