A gaseous hydrocarbon contains 82.76% of carbon. Given that its vapour density is 29,find its molecular formula. [C = 12, H = 1]

Explanation

Empirical Mass of `C_2 H_5 = 12 xx 2 + 1 xx 5 = 24 + 5 = 29`
Mass = `2xx ` Vapour density [Given , Vapour density= 29]
`= 2xx 29 = 58 g `
`n = ("Molecular mass")/(Empirical formula mass") = (58)/(29) = 2`
Molecular formula `= 2xx C_2 H_5 = C_4 H_(10)`