`0*05 " M " NaOH` solution offered a resistance of `31*6` ohm in a conductivity cell at 298 K. If the cell constant of the cell is `0*367 cm^(_1)` calculate the molar conductivity of the NaOH solution.

(a) Apply Kohlrausch law of independent migration of ions, write the expression to determine the limiting molar conductivity of calcium chloride. (b) Given are the conductivity and molar conductivity of NaCI solutions at 298 K at different concentrations : Compare the variation of conductivity and molar conductivity of NaCI solutions on dilution. Give reason. (c) 0.1 M KCI solution offered a resistance of 100 ohms in conductivity cell at 298 K. If the cell constant of the cell is 1.29 cm^(-1) , calculate the molar conductivity of KCI solution.

A 0.05 M NaOH solution offered a resistance of 31.6 ohms in a conductivity cell. If the cell constant of the conductivity cell is 0.378 cm^(-1) , determine the molar conductivity of sodium hydroxide solution at this temperature.

A 0.05 M NaOH solution offered a resistance of 31.6 Omega in a conductivity cell at 298 K. If the cell constant of the conductivity cell is 0.367 cm^(-1) , find out the specific and molar conductance of the sodium hydroxide solution.

A 0.05 M NH_(4)OH solution offers the resistance of 50 ohm to a conductivity cell at 298 K. If the cell constant is 0.50cm^(-1) and molar conductance of NH_(4)OH at infinite dilution is 471.4ohm^(-1)cm^(2)mol^(-1) , calculate : Molar conductance

A 0.05 M NH_(4)OH solution offers the resistance of 50 ohm to a conductivity cell at 298 K. If the cell constant is 0.50cm^(-1) and molar conductance of NH_(4)OH at infinite dilution is 471.4ohm^(-1)cm^(2)mol^(-1) , calculate : Specific conductance

A 0.05 M NH_(4)OH solution offers the resistance of 50 ohm to a conductivity cell at 298 K. If the cell constant is 0.50cm^(-1) and molar conductance of NH_(4)OH at infinite dilution is 471.4ohm^(-1)cm^(2)mol^(-1) , calculate : Degree of dissociation

A 0.05 M NH OH solution offers the resistance of 50 ohms to a conductivity cell at 298 K. If the cell constant is 0.50 cm^(-1) and molar conductance of NH_(4)OH at infinite dilution is 471.4 ohm^(-1) cm^(2) "mol"^(-1) calculate : (i) Specific conductance (ii) Molar conductance (iii) Degree of dissociation.

The resistance of 0.01 M NaCl solution at 25°C is 200 ohm.The cell constant of the conductivity cell used is unity. Calculate the molar conductivity of the solution.

The resistance of 0.01N solution of an electrolysis is 210 Omega at 298 K with a cell constant of 0.88 cm^(-1) . Calculate the conductivity and equivalent conducitivty of the solution.

The resistance of a 0.01N solution of an electrolyte was found to 210 ohm at 298K using a conductivity cell with a cell constant of 0.88 cm^(-1) . Calculate specific conductance and equivalent conductance of solution.