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For a first order reaction, show that t...

For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction.

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`t=(2.303)/(k)xx"log"(R^(0))/(R )`
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For a first order reaction, show that the time required for 99% completion is twice the time required for the completion of 90% of reaction.

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